Introductory Problem!

What is the maximum height reached by a ball thrown vertically upward with an initial velocity 6 m/s 6 \text{ m/s} ?

Note: Take g = 10 m/s 2 g = 10 \text{ m/s}^{2} .

Provide your answer in cm \text{cm} .


The answer is 180.

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1 solution

Swapnil Das
May 27, 2015

Maximum height reached = u 2 2 g \frac { { u }^{ 2 } }{ 2g }

Getting the values plugged, we get 6 2 20 = 1.8 m = 180 c m \frac { { 6 }^{ 2 } }{ 20 } = 1.8 m = 180 cm

Yeah..!! An exclusive use of NEWTON'S third law of motion...Carefully drafted question...liked it..!!! :)

Rahul Singh - 6 years ago

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Thank You! I hope I could create harder problems in future!

Swapnil Das - 6 years ago

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But I think this set was meant for the beginners...Try raising the level of questions gradually...

Rahul Singh - 6 years ago

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@Rahul Singh Yes, but I am trying to develop my set as well as myself, well thank you for solving my set!

Swapnil Das - 6 years ago

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@Swapnil Das Well I loved it..!!! Reminded me of the time when I was fascinated for PHYSICS for the 1st time...

Rahul Singh - 6 years ago

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