Easy Sigma Problem

Algebra Level 1

n = 1 4 n 2 \displaystyle \sum_{n=1}^4 n^2


The answer is 30.

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6 solutions

Justin Barlas
Jan 4, 2015

1 2 + 2 2 + 3 2 + 4 2 = 30 1^2 + 2^2 + 3^2 + 4^2=30

1 + 4 + 9 + 16 = 30 1+4+9+16=30

Why don't you use formula for Sum of squares of first n natural numbers \text {Sum of squares of first n natural numbers}

Sai Ram - 5 years, 9 months ago

The formula for sum of squares of n n numbers will come in handy in this problem.

The formula is:

n 2 = ( n ) ( n + 1 ) ( 2 n + 1 ) 6 \sum n^2 = \frac {(n)(n + 1)(2n + 1)}{6}

It is easy to see that the sum of the squares of first four natural numbers is 30 30

Using the formula is overkill here!

Pranjal Jain - 6 years, 5 months ago

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Though it is, the formula is a foolproof method. Any person with a little bit of common sense can use his skills to guess a number and use the hit and trial method. With the formula method, you can come up with the answer in a matter of seconds!

Mohnish Chakravarti - 6 years, 5 months ago

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No, it's really not needed here. Don't overcomplicate things. Here, knowing what the sigma operator means 'sum' is the important bit. It's much easier to add 1, 4, 9 and 16 than it is to put numbers into that formula (assuming you even know that formula - most people won't because sums of squares isn't exactly a common thing to need). This is a level 1 question after all...

Paul Smith - 5 years, 8 months ago
Nikhil Raj
May 30, 2017

ANSWER = n = 1 4 n 2 = 1 2 + 2 2 + 3 2 + 4 2 = 1 + 4 + 9 + 16 = 30 \displaystyle \sum_{n=1}^4n^2 = 1^2 +2^2 +3^2 + 4^2 = 1 + 4 + 9 + 16 = \boxed{30}

Caeo Tan
Jun 28, 2015

1^2+2^2+3^2+4^2

1+2^2=5

3^2+4^2=5^2=25

5+25=30

Paola Ramírez
Jan 6, 2015

( 4 ) ( 5 ) ( 9 ) 6 = 30 \frac{(4)(5)(9)}{6}=30

Vishal S
Jan 5, 2015

n = 1 4 n 2 = n ( n + 1 ) ( 2 n + 1 ) 6 = 4 ( 5 ) ( 9 ) 6 = 30 \displaystyle\sum_{n=1}^4 n^2=\dfrac{n(n+1)(2n+1)}{6} = \dfrac{4(5)(9)}{6}= 30

Remember to wrap math in \­( ... \­) or \­[ ... \­] to ensure proper formatting.

Justin Barlas - 6 years, 5 months ago

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Okay .Here after I'l follow it

Vishal S - 6 years, 5 months ago

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I have edited your latex. Please check if I did any change in your method. You may use this as a reference for later use. Click "Edit" to see latex.

Pranjal Jain - 6 years, 5 months ago

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@Pranjal Jain Thanks for your help

Vishal S - 6 years, 5 months ago

Just a suggestion

Justin Barlas - 6 years, 5 months ago

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