A geometry problem by Krishna Ar

Geometry Level 3

A vector P P makes angles α , β , γ \alpha, \beta, \gamma with the three co-ordinate axes respectively. Then the value of sin 2 α + sin 2 β + sin 2 γ \sin^2 \alpha +\sin^2 \beta+ \sin^2 \gamma ?

Note: The vector is in a 3-d plane.

2 0 1 3

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2 solutions

sin 2 α + sin 2 β + sin 2 γ = ( 1 cos 2 α ) + ( 1 cos 2 β ) + ( 1 cos 2 γ ) = 1 + 1 + 1 ( cos 2 α + cos 2 β + cos 2 γ ) = 3 1 = 2 \sin ^ 2 \alpha + \sin ^2 \beta + \sin ^2 \gamma \\= (1-\cos ^ 2 \alpha) + (1 -\cos ^2 \beta) + (1-\cos ^2 \gamma) \\ = 1+ 1+ 1 - ( \cos ^ 2 \alpha + \cos ^2 \beta + \cos ^2 \gamma) \\ = 3 - 1 \\ = 2

I just made a guess. This happens in a right angled triangle... :-P

Satvik Golechha - 6 years, 8 months ago

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Oh really -_-

Krishna Ar - 6 years, 8 months ago

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Yes \Huge {\text{Yes}}

Satvik Golechha - 6 years, 8 months ago

Or just s i n 2 α + c o s 2 α + s i n 2 90 {sin}^{2}\alpha + {cos}^{2}\alpha + {sin}^{2}90

Kartik Sharma - 6 years, 8 months ago
Hansraj Sharma
Sep 25, 2014

c o s 2 α + c o s 2 β + c o s 2 γ = 1 s o a n s w e r i s 2. { cos }^{ 2 }\alpha +{ cos }^{ 2 }\beta +{ cos }^{ 2 }\gamma =1\\ so\quad answer\quad is\quad 2.

how do you do this??

Aya Alaa - 6 years, 8 months ago

Can you add an explanation of where you obtained the first equality from?

Calvin Lin Staff - 6 years, 8 months ago

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It is a basic identity in Vector Algebra.

Why is this problem flagged?

Agnishom Chattopadhyay - 6 years, 8 months ago

Yeah, why is this flagged?

Krishna Ar - 6 years, 8 months ago

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The report stated "You should clarify that this is a vector in 3-D, instead of a vector in higher dimensions."

I agree with this, and see that the problem has been updated.

Calvin Lin Staff - 6 years, 8 months ago

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@Calvin Lin That's alright. Thanks. I felt that it was self-understood though

Krishna Ar - 6 years, 8 months ago

sir i want to ask what is the sum of three angles that a 3-d vector makes
with all 3 axes ??

Rishabh Jain - 6 years, 8 months ago

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