We all know that a b c ∣ ∣ ∣ 1 0 0 a + 1 0 b + 1 c because a b c = 1 0 0 a + 1 0 b + 1 c .
But are there any three distinct digits a , b , c such that a b c ∣ ∣ ∣ 1 0 0 a 1 0 b 1 c ?
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How many solutions are there?
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with any digits = 0, or all a, b, c nonzero?
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a can't be zero. b and c can.
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@Thành Đạt Lê – Just 9, then
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@Michael Mendrin – Can you show all the solutions? (Sorry for taking your time away.)
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1 9 2 1 0 0 1 1 0 9 1 2 = 5 2 1 4 1 1 for example
Here are all the possible numbers
1 6 5 , 1 6 6 , 1 9 2 , 2 1 0 , 2 3 0 , 2 3 2 , 3 1 0 , 7 6 6 , 7 9 1