Exponent rules #2

Algebra Level 2

3 × 2 n + 4 × 2 n + 2 2 n 2 n 1 = ? \large \frac{3 \times 2^n + 4 \times 2^{n+2}}{2^n - 2^{n-1}} = ?


The answer is 38.

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1 solution

Blan Morrison
Jan 22, 2018

Relevant wiki: Rules of Exponents

First, we can simplify the expression:

3 × 2 n + 2 n + 4 2 n 1 \frac{3\times2^n+2^{n+4}}{2^{n-1}}

Then, we can pull out the common term in the numerator:

2 n ( 3 + 2 4 ) 2 n 1 \frac{2^n(3+2^4)}{2^{n-1}}

Simplify:

2 1 ( 3 + 16 ) 2^1(3+16)

And simplify again:

2 × 19 = 38 2\times19=\boxed{38}

Why are you setting n = 1 ?

Adrian Ronayne - 3 years, 4 months ago

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I didn't. Which step are you talking about?

Blan Morrison - 3 years, 4 months ago

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Post first simplify step n is set to 1 . For example 2^n becomes 2^1 ?

Adrian Ronayne - 3 years, 3 months ago

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@Adrian Ronayne Let's ignore the coefficient: 2 n 2 n 1 \frac{2^n}{2^{n-1}}

Because of the rules of exponents, we know that a m a n = a m n \frac{a^m}{a^n}=a^{m-n}

2 n 2 n 1 = 2 n ( n 1 ) = 2 1 \frac{2^n}{2^{n-1}}=2^{n-(n-1)}=2^1

Blan Morrison - 3 years, 3 months ago

Very cute problem :)

MAINAK CHAUDHURI - 3 years, 2 months ago

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