4 2 0 2 0 − 4 2 0 1 9 = ?
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4 2 0 2 0 − 4 2 0 1 9 = 4 2 0 1 9 × ( 4 − 1 ) = 4 2 0 1 9 × 3
Great! But I don't understand where did you get the ( 4 − 1 ) from?
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Well, 4 2 0 2 0 = 4 ( 4 2 0 1 9 ) , hence there is a 4 .
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Then where do you get the − 1 from in the ( 4 − 1 )?
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@Yajat Shamji – @Yajat Shamji He took 4 2 0 1 9 common
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@Aaghaz Mahajan – Ok. Thanks a lot. Now I understand.
4 2 0 2 0 − 4 2 0 1 9 = 4 ( 4 2 0 1 9 ) − 1 ( 4 2 0 1 9 ) = ( 4 − 1 ) 4 2 0 1 9 :)
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@Jeff Giff – Ok. Thanks a lot. Now I understand.
@Jeff Giff – A minor typo, you wrote 4 2 0 1 9 instead of 4 2 0 1 9
solve it with the same way
4 2 0 1 9 4 2 0 2 0 = 4 ⇒ 4 2 0 2 0 − 4 2 0 1 9 = 3 × 4 2 0 1 9 ≈ 6 4 Duoquadrigentillion (Give or take a few)
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4 2 0 2 0 − 4 2 0 1 9
= 4 2 0 1 9 x 4 - 4 2 0 1 9 x 1
= 4 2 0 1 9 x ( 4 − 1 )
= 4 2 0 1 9 x 3
In generality we also have:
4 n + 1 - 4 n
= 4 n x 4 - 4 n x 1
= 4 n x ( 4 − 1 )
= 4 n x 3
AND:
A n + 1 - A n
= A n x A - A n x 1
= A n x ( A − 1 )