I have 3 circles whose ratio of radii is 1 : 2 : 3 . I draw these 3 circles such that they are externally tangent to each other. I then draw another circle such that it is internally tangent to all these 3 circles.
Of all the 4 circles drawn, what is the ratio of areas between the largest circle and the smallest circle?
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Challenge Master Note: What would the answer be if I replaced the word "internally" with "externally" in the problem statement?
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r = 2 3 6
so, answer is 5 2 9 3 6
Answer is wrong:
Ans. = ( 3 ÷ 2 3 6 ) 2 = 1 3 2 4 1
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No, the answer is ( 3 ÷ 2 3 6 ) 2 = 1 3 2 4 1 .
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@Pi Han Goh – Dammit! Biggest circle, not circle with radius 1.
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Let the radius or the 4th circle be r . By Descartes' Circle Theorem , we have
− r 1 ⟹ r = 1 1 + 2 1 + 3 1 − 2 2 1 + 3 1 + 6 1 = 6 1 1 − 2 = − 6 1 = 6
Therefore, the ratio between the areas of the of the largest and smallest circles is 1 2 6 2 = 3 6 .