Externally and internally tangent

Geometry Level 3

I have 3 circles whose ratio of radii is 1 : 2 : 3 1:2:3 . I draw these 3 circles such that they are externally tangent to each other. I then draw another circle such that it is internally tangent to all these 3 circles.

Of all the 4 circles drawn, what is the ratio of areas between the largest circle and the smallest circle?


The answer is 36.

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1 solution

Sharky Kesa
Jan 4, 2017

Let the radius or the 4th circle be r r . By Descartes' Circle Theorem , we have

1 r = 1 1 + 1 2 + 1 3 2 1 2 + 1 3 + 1 6 = 11 6 2 = 1 6 r = 6 \begin{aligned} -\frac{1}{r} &= \frac{1}{1} + \frac{1}{2} + \frac{1}{3} - 2\sqrt{\frac{1}{2}+\frac{1}{3}+\frac{1}{6}}\\ &= \frac{11}{6} - 2\\ &=-\frac{1}{6}\\ \implies r&=6\\ \end{aligned}

Therefore, the ratio between the areas of the of the largest and smallest circles is 6 2 1 2 = 36 \frac{6^2}{1^2}=36 .

Great!

Challenge Master Note: What would the answer be if I replaced the word "internally" with "externally" in the problem statement?

Pi Han Goh - 4 years, 5 months ago

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r = 6 23 r=\dfrac{6}{23}

so, answer is 36 529 \frac{36}{529}


Answer is wrong:

Ans. = ( 3 ÷ 6 23 ) 2 = 132 1 4 \text{Ans. } = \left (3 \div \dfrac{6}{23} \right)^2 = 132 \dfrac{1}{4}

Sharky Kesa - 4 years, 5 months ago

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No, the answer is ( 3 ÷ 6 23 ) 2 = 132 1 4 \left( 3 \div \dfrac 6{23} \right)^2 = 132 \dfrac14 .

Pi Han Goh - 4 years, 5 months ago

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@Pi Han Goh Dammit! Biggest circle, not circle with radius 1.

Sharky Kesa - 4 years, 5 months ago

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