Eyes Wide Open...
What is the no. of solutions to: x 2 0 1 6 + ( 2 0 1 6 ! + 1 ! ) x 2 0 1 5 + ( 2 0 1 5 ! + 2 ! ) x 2 0 1 4 + . . . . . + ( 1 ! + 2 0 1 6 ! ) = 0
x ≥ 0
The answer is 0.
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1 solution
Hey.. its pre rmo 2016 question. I qualified it last year. 50/80. Nice exam.
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This one is very easy.
You did? I couldn't. Was not eligible due to age.
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Ok. TRY Giving this year.
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@Md Zuhair – Sure. Am going to.
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@Rajdeep Ghosh – You did qualified this time?
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@Md Zuhair – Yeah. Score-12. I didn't get any rough paper, otherwise was expecting more than 15. You?
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@Rajdeep Ghosh – Same here. Score 13. No rough sheets provided. Where was ur centre. this time its hindu school. I even gave prmo at hindu school
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@Md Zuhair – Yeah Hindu School
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What is the no. of solutions to:
x 2 0 1 6 + ( 2 0 1 6 ! + 1 ! ) x 2 0 1 5 + ( 2 0 1 5 ! + 2 ! ) x 2 0 1 4 + . . . . . + ( 1 ! + 2 0 1 6 ! ) = 0
Look at the underline.
It's a positive constant and the rest of the L.H.S is positive since x is non-negative.So, L.H.S is positive but R.H.S is 0
BOOM!
Bet you didn't see that.(If you couldn't solve it.)