Once fully turned on, an old kitchen faucet produces a slow but steady flow of water, free of bubbles and turbulent flow.
Thanks to the pull of gravity, the stream of water accelerates as it falls.
Does the shape of the stream change as the water falls?
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Maybe its just me but it did not say vacuum or anything that said it came to an end. I just pictured the angel falls where the water from the water fall never touches the ground as a stream instead it falls like a mist.
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Flow of water in waterfalls is very turbulent, since large amounts of water move at great velocities. (Thats why they appear so white and bubbly). The continuity equation will not be valid there
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Is "large amounts" relevant or is it safe to assume that the water from the facet also would become turbulent and create a mist?
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@Magnus Drogseth – I think the mist formation has to do with the velocity it gains as it falls, but I dont know exactly
Agree. There are at least two correct answers to this question.
The flow is constant because the tap is opened to the max and the internal friction between pipe and water is at a equilibrium. When the water comes out of the tap. the friction of the pipe walls is no longer present. Assuming it is pointing towards the ground, gravity will be pulling the water and accelerating it. So the local velocity of the water will increase, while the flow rate remains the same. Thus, the stream will become narrow from the increasing local velocity of the water.
True, however wouldn't air resistance and the constant increase cause the stream to eventually break into drops? The drops would create a mist with a cross section greater than that at the faucet. This would require the sink to be unusually far from the faucet, for example 200 feet.
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It is assumed that the flow remains streamlined the entire time, though that might not be the case in real life.
If V' = 0, don't we get A' x + A x' = 0 after product rule?
Why does A' = 0 when we later consider A 1 != A 2?
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I was expecting someone to ask that😅 Actually, the continuity equation uses the concept of constant volume flux , which is defined as A v .
What's with the Bernoulli-effect
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Bernoulli- effect all has to do with the change in energy of liquid per mass(KE+PE) due to pressure energy per mass
I thought acceleration is different from speed or is that velocity. Acceerlation includes direction. So if the direction changes, that decreases acceleration
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The magnitude is all that matters here, since the only direction concerned is down.
The stream does not narrow indefinitely.
It gets narrower, until it starts forming separate drops because of surface tension, which then continues to fall as water drops without becoming narrower, even as they continue towards accelerate to terminal velocity. Instead of narrowing, the drops get more spaced out as they fall, so that the flow rate remains uniform with height.
V=Ax so why does V'=const not become
A' x + A x' = const via product rule
Why can we set A' = 0 when later in the argument we consider A 1! = A 2?
Thanks
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First of all, formula V = A x applies only in special case when indeed cross sectional area doesn't change along x . In general case, we need an integral: V = ∫ A ( x ) d x which can be manipulated by inverse chain rule to become: V = ∫ A ( x ) d t d x d t = ∫ A ( x ) v d t Fundamental theorem of calculus now says that derivative of V with respect to t is just: d t d V = A ( x ) v .
we could imagine that a group of people gathering in front of gate. Once gate open , queue all people run through gate and rush into Narrow passage with the regular acceleration.So some people ahead of group move a bit earlier than people following them, then distance between them will increase, people need not shoulder by shoulder, width of queue is narrow
Great example
Perfect. Thats why it will widen after a short fall , like a waterfall
What if everyone is ready to when the doors open, and everybody starts moving exactly at the same time ? Once the faucet is fully open, why would a drop "wait" for the one in front of it ?
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firstly, it is hard to for people moving exactly at the same time, because people wait behind until people stand in front of row walk, in order to make room for people stand in back of row. likewise,since drop water is not solid,if it is solid,drop move at same time, but it is not, the drop have to wait unit one in front of it.
As the water falls down it moves faster than the water above, due acceleration due to gravity ,hence stretching the stream and becoming narrower .
Thanks so much for your answer honestly it was the only one that I could understand without a paper and pen
The answer to this question is quite practical actually. As we know that because of the pull of gravity, the water is accelerating towards the earth, we know that the velocity is increasing as well.
Therefore, the equation will look like this: A1*V1= rate of flow, as the water is maintaining a constant rate of flow. Where A is the cross-sectional area and V is the Velocity
Therefore, if A1 V1= Constant Then, A2 V2= Constant
And, as we know that V is an increasing quantity, then, naturally, A has to become a decreasing quantity.
So the answer is: Yes, the stream will become narrower.
We already know that the stream of water will narrow according to the continuity equation, but it does not narrow indefinitely, as we tend to observe the phenomenon known as Plateau-Rayleigh instability beyond a certain height, where the narrowed neck of water collapses into separate droplets due to a property of surface tension being the desire to acquire the least surface area possible. The distance between the droplets, however, increases over time as a necessity of the flow rate remaining constant.
To maintain the volume flow rate which is constant for a streamlined flow the stream narrows as its speed increases due to gravity.
See, you don’t need much math for this one. Go turn on your sink (and make sure the stream isn’t bubbly) and WATCH! :D
The equation of continuity of stream-lined flow of fluid // Density(p) * Cross section area (A) * Velocity(v)= constant // so the liquid won't compress indefinitely and it will do so in proportion.
Just from a layman's perspective, air resistance alone would cause the stream to narrow
The water coming out of the faucet is flowing at a constant rate, but as it continues accelerating, it starts to "spread out". Surface tension, however, keeps it from forming into drops just yet, so it just becomes a tighter column.
Just yet? But what if the facet is 500 feet above the sink?
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The stream of water tends to maintain it's rate of flow of water, d t d V , where V is the volume. Thus, it obeys the continuity equation.
d t d V = c o n s t a n t
A ⋅ d t d x = c o n s t a n t
A 1 v 1 = A 2 v 2 , where A is the area of cross section of the stream and v = d t d x = velocity of the water.
As the water falls, it accelerates, thus gaining speed. According to the above equation, the area of cross section should decrease, and hence the stream becomes narrower.