Fermat's Last Theorem

Algebra Level 3

How many solutions ( a , b , c , n ) (a,b,c,n) are there to the equation

a n + b n = c n a^n+b^n=c^n

for n > 2 n>2 ?

Uncountably Infinitely many 0 Finitely many Countably Infinitely Many

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3 solutions

Maharnab Mitra
Apr 2, 2014

Taking a = b = c = 0 a=b=c=0 we get 0 n + 0 n = 0 n 0^n+0^n = 0^n which is satisfied when n n is a non-zero real number. So, it has uncountably infinitely many solutions.

But that is a trivial solution.

Isaac Thomas - 6 years, 5 months ago

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There were never constraints put on the variables, besides n.

Ryan Tamburrino - 6 years, 5 months ago

when you let a=b=c=0.

Isaac Thomas - 6 years, 5 months ago

I think fermat's last theorem is valid for only positive integers

U Z - 6 years, 5 months ago
Logan Dymond
Apr 1, 2014

For any choice of a , b , n a,b,n if c = a n + b n n c=\sqrt[n]{{a^n+b^n}} then the equation is satisfied. Since there are uncountably infinitely many choices for a , b , n a,b,n , the solution set is uncountably infinite.

April Fools

Logan Dymond - 7 years, 2 months ago

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Awww, got me there :( Learned my lesson to read problems more accurately.

Sean Ty - 6 years, 10 months ago

WHY IS FERMAT"S LAST THEOREM IN THE TITLE!!!!! I was totally fooled by this one.

Anik Chakrabarty - 7 years, 2 months ago

Ohh please!? It's really not a good joke. I'm in level 5 and lost lots of ratings by assuming this question as a real Fermat's Last Theorem . At least in the title you can add a question mark or you could make this as an unrated problem . If it is permitted on Brilliant, I can also do the same thing as an April Fools's prank but I will NOT do such thing as that. Grow up kid!

Tunk-Fey Ariawan - 7 years, 2 months ago

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This question is unrated as on 4/2/2014 7:54 PM IST. How did you lose your rating?

Why are you blaming the author of the question for your own mistake?

Though the title is somewhat misdirecting, you could have solved it correctly if you had read the question properly.

Vijay Raghavan - 7 years, 2 months ago

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You may want to take a look this: As you can see this was a rated problem .

Now, you see this note by Calvin: How To Get Your Problem Shared/Liked On Brilliant . Read point no. 1: Simplify your statements and state them precisely. Do not try to be tricky , point no. 4: Choose a title which reflects the content of the problem , and then point no. 9: Avoid any ambiguity; define uncommon terms .

Now, imagine this one: How if there are other members also make problems like this as a prank ?? You as a level 5 member definitely know how hard a level 5 member earn points or maintain his rating. Read also this note by Michael Mendrin: A problem for Level 5 users in solving low Level problems .

Tunk-Fey Ariawan - 7 years, 2 months ago

I'm sorry for making the problem rated, I did not realize that I could make it unrated. I had no intention of causing people to lose their most important, meaningful, hard earned ranks, but I now realize the consequences of my actions. I will reevaluate my maturity and hopefully one day take your advice and finally grow up.

Logan Dymond - 7 years, 2 months ago

No need to be so angry. We are here to enjoy and share problems not bicker about petty levels and ratings..

Thaddeus Abiy - 7 years, 2 months ago

This problem is better taken as a lesson for us. Calm down.

Sean Ty - 6 years, 10 months ago

oh wait darn yeah they dont have to be integers... =p >=(

faraz masroor - 7 years, 2 months ago

Aw i thought it was the real fermat last theorem :( you got me there

Samuel Samuel - 6 years, 5 months ago

Wait, so is 'Uncountably Infinitely Many' correct? I know that it's supposed to be a fool question and all, but WHAT IF YOU MAKE OTHER PEOPLE LOSE RATING D: So is the correct answer indeed 0?

Math Calculus - 7 years, 2 months ago

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No,

one such valid solution is ( 1 , 1 , 2 π , π ) (1,1,\sqrt[\pi]{2},\pi)

Logan Dymond - 7 years, 2 months ago

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Oh.... It doesn't have to be positive integers. WHY YOU PUT FERMAT'S LAST THEOREM IN TITLE!!! D:

Math Calculus - 7 years, 2 months ago

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@Math Calculus April fools! Always assume the domain over the reals unless otherwise specified.

Trevor B. - 7 years, 2 months ago

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@Trevor B. According to whom?

Oliver Bel - 7 years, 2 months ago

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@Oliver Bel Rule of thumb, it's certainly not a law.

Logan Dymond - 7 years, 2 months ago

@Oliver Bel Never assume anything in math.

For example, in the heading of AP Calculus tests and most of the math competitions I've been in, it was said in the heading of the paper that the domain of all functions is the real numbers unless otherwise specified.

Trevor B. - 7 years, 2 months ago
Kevin Mo
Apr 2, 2014

Be glad that it is now unrated. This is the worst April Fools joke ever, considering that it does damage to someones hard-earned rating.

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