Find the answer

Great problem! Let the answer be $x$ . Thus, $|x-1|=x$ . It is obvious that the points that satisfy this equation are one away from each other and have 0 as their axis of symmetry. From this, the answer is obviously $\boxed{0.5}$ . It is much more rigorous to proceed as following, however.

Case 1: $x-1$ is positive. Thus $x-1=x$ which is impossible.

Case 2: $x-1$ is negative, in which case it reverses as $1-x$ . Solving, $1-x=x \Longrightarrow 2x=1 \Longrightarrow x=\boxed{0.5}$ .

Let the answer be $x$ .

So $|x-1|=x$

$(x-1)^2=x^2$

$x^2-2x+1=x^2$

$-2x+1=0 \Rightarrow x=\boxed{\frac{1}{2}}$

X = |1-X| X = 1-X OR X = -1+X (WHICH IS NOT POSSIBLE) 2X = 1 X = 1/2 = 0.5

x=|x-1| => x=0.5

Let the answer be x.

We have x=|x-1|.

If x-1>0, we have x=x-1, which is clearly impossible. And x=0 doesn't work. If x-1<0, we have x=-x+1, so x=.5 is our answer.