When multiplied out, the number above consists of 9 digits, each appearing once. Which digit from 0 to 9 does not appear ?
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Of course, one approach is to multiply out the number and see that we get 2 × 6 5 3 × 7 3 3 × 9 7 7 = 9 3 5 2 8 0 1 4 6 and hence the missing number is 7. That was how I created this problem, but it is not how I expect you to solve it.
Let's consider modulo 9. Let the number be expressed as N . We have
N ≡ 2 × 6 5 3 × 7 3 3 × 9 7 7 ≡ 2 × 5 × 4 × 5 ( m o d 9 ) ≡ 2 ( m o d 9 ) ( m o d 9 )
The sum of all 10 digits is 0 + 1 + 2 + … + 9 = 4 5 . If the digit a was not used, then the sum of the digits is 4 5 − a .
Since the remainder when divided by 9 is equal to the remainder of the sum of the digits when divided by 9, this tells us that 4 5 − a ≡ 2 ( m o d 9 ) . Hence, we can conclude that a = 7 .