Find the Number of Solutions to Simple Equations

Algebra Level 3

{ a + b + c + d = 20 , a b + a c + a d + b c + b d + c d = 150. \left\{\begin{array}{cc}a+b+c+d &=& 20,\\ ab+ac+ad+bc+bd+cd &=& 150.\end{array}\right.

Find the number of positive ordered quadruplets ( a , b , c , d ) (a,b,c,d) that satisfy the two equation above.


The answer is 1.

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1 solution

Alan Yan
Oct 14, 2015

It is easy to see that a 2 + b 2 + c 2 + d 2 = 100 a^2 + b^2 + c^2 + d^2= 100

By Q M A M QM - AM , we have that a 2 + b 2 + c 2 + d 2 4 a + b + c + d 4 \sqrt{\frac{a^2 + b^2 + c^2 + d^2}{4}} \geq \frac{a+b+c+d}{4}

However they are equal. Equality holds when a = b = c = d = 5 a = b = c = d = 5 and this is the only solution.

Exactly Same Way

Kushagra Sahni - 5 years, 8 months ago

what is qm please do explain

Kaustubh Miglani - 5 years, 8 months ago

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Quadratic Mean.

Kushagra Sahni - 5 years, 8 months ago

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so what is the formula for this

Kaustubh Miglani - 5 years, 8 months ago

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@Kaustubh Miglani Quadratic mean is what Alan has written on the RHS

Kushagra Sahni - 5 years, 8 months ago

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@Kushagra Sahni is it the sum of squares of observations divided by no. of observations

Kaustubh Miglani - 5 years, 7 months ago

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@Kaustubh Miglani ( a + b + c + d ) 2 = a 2 + b 2 + c 2 + d 2 + 2 ( a b + a c + a d + b c + b d + c d ) (a+b+c+d)^2 = a^2 + b^2 + c^2 + d^2 + 2(ab + ac + ad + bc + bd + cd)

Alan Yan - 5 years, 7 months ago

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