Finding the value of x of basic operations

$\dfrac {10x+20}2 = 3(2x-5)$

$\Rightarrow \dfrac{10(x+2)}{2} = 6x-15$

$\Rightarrow 5(x+2)= 6x-15$

$\Rightarrow 5x+ 10= 6x-15$

$\Rightarrow 5x = 6x - 15 - 10$

$\Rightarrow 5x - 6x = -25$

$\Rightarrow x = 25$

Hence $x= \boxed{25}$

The solution is your own solution...

10x + 20 = 2 × (2x-5) × 3

10x + 20 = 6(2x-5)

10x + 20 = 12x - 30

2x = 50

x = 25

Note : After you have obtained the answer, substituted back into equation, you will get 135 = 135 , balance...

Thank you, salam 1 Malaysia....