Normalize this
If 1 2 8 = x 2 , find the digit sum of x .
Note that a b is the number a in base b .
The answer is 2.
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3 solutions
I am not able to open reply of Jake Lai. 1 2 8 = 1 0 0 1 2 i s N O T c o r r e c t .
1 2 8 = 1 × 8 + 2 = 1 × 2 3 + 1 × 2 = 1 0 1 0 2
I think there is a typo.It should be 1 0 1 0 2
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That's the answerI gave and it's marked as wrong! This site is getting very poor.
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It is asking for sum of digits .Did u notice that? So answer is not 1010 .Answer is 2.
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@Gautam Sharma – You're right Guatam, I missed that. Apologies.
There's a nice algorithm for calculating the representation of a base 1 0 number in base x where x ∈ Z + .
You simply divide the number by x and collect the remainder in each step. This process is repeated till you get 1 as the quotient. Now, simply pile up the remainders from last to first and you get the required representation.
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The answer is 2 because it was clearly stated that find the digit sum of x which is 1+0+1+0 = 2
1 = 001 & 2 = 010
So Ans = 2
N O T c o r r e c t .
1 0 8 = 8 1 0 , 2 8 = 2 1 0 , ⟹ 1 2 8 = 1 0 1 0 2 0 = 1 , 2 1 = 2 , 2 3 = 8 , 2 4 = 1 6 > 1 0 . 1 0 1 0 = 8 1 0 + 2 1 0 = 1 0 0 0 2 + 1 0 2 = 1 0 1 0 2 . 1 + 0 + 1 + 0 = 2 1 0 .