From 9 9 9 9 9 9 9 9 9 8 8 8 8 8 8 8 8 7 7 7 7 7 7 7 6 6 6 6 6 6 5 5 5 5 5 4 4 4 4 3 3 3 2 2 1 subtract half of it first, then subtract 3 1 of the remaining number, next subtract 4 1 of the remaining number, and so on, until 9 9 9 9 9 9 9 9 9 8 8 8 8 8 8 8 8 7 7 7 7 7 7 7 6 6 6 6 6 6 5 5 5 5 5 4 4 4 4 3 3 3 2 2 1 1 of the remaining number is subtracted. What is the final resulting number?
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You should clarify that you used telescoping product.
Karthik, please be responsible when setting the level of a problem. This problem is clearly not a level 5. If you think that this is at the difficulty of a level 5 problem, that will make me question if you do deserve to be at level 5.
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I am sorry sir. I wont do this again.
Yes, I do not deserve a level 5, because I got it by solving over-rated problems on brilliant, to be frank. I could never solve your Level 5 Challenge picks. I want to de-level now, then you can later see that I deserve a level 5 or not. :(. But one thing, what was the necessity that you had to comment in such a de-moralising manner? You could've just informed me that I should not be setting level 5 for such problems.
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Thanks for understanding. We keep the ratings system in line, but it can still be abused by a problem creator who sets the level to be significantly higher than it should be. This does result in perceptions of "rating system doesn't work", which lowers the confidence that others have with regards to its relevance. As such, abuse of this system is not tolerated, nor is it appreciated by the community.
This is not the first problem of yours which has an artificially high level. We have gone through and edited several of your other problems, which is why you have received the above notice.
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@Calvin Lin – Why couldn't it be just a simple notice, rather than such a comment ? I am sorry for what I have done, and do de-level my profile.
@Calvin Lin De-level my account to level 1 please. Thank you.
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STRATEGY
Whenever such large numbers are given in some questions, it is better to first try to check it for smaller numbers or for generally any number.
SOLUTION
Let us substitute the large number given in the question for x . Then, we observe that if we remove half of a quantity, half is remained and when 3 1 r d of a quantity is removed, 3 2 remains, and so on. So, we can now simplify these subtractions and write the final result as a telescopic product ( x x − 1 … ( 4 3 ( 3 2 ( 2 1 x ) ) ) ) = 1 .