Friction in Elastic collision?

A small spherical ball undergoes an elastic collision with a rough horizontal surface. Before the collision, it is moving at an angle of θ \theta with the horizontal. Assume that friction f = μ N f=\mu N during the contact period, where N N is the normal reaction and μ \mu is the coefficient of friction.

Find the value of θ \theta (in degrees) to the nearest integer such that the horizontal range of the ball after hitting the surface is maximized, given μ = 3 2 \mu=\frac{\sqrt{3}}{2} .


The answer is 15.

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1 solution

Rajdeep Brahma
Apr 22, 2017

Velocity along Y Y direction is same in magnitude before and after the collision (elastic).

Let the normal reaction be N N .

Impulse = N . t = 2 m v ( sin θ ) N.t = 2mv (\sin \theta) .

Along x x axis, I = f . t = μ N . t = 2 μ m v . ( sin θ ) I = f.t = \mu N.t = 2\mu m v.(\sin \theta) .

Using d I = d P dI=dP , we get, v x v_x (velocity along x x after collision) = v ( ( cos θ ) 2 μ sin ( θ ) ) v((\cos \theta)-2\mu \sin(\theta)) .

Range= 2 v ( sin θ ) g × v x \dfrac{2v(\sin \theta)}{g} \times v_x

Maximize R to get cot ( 2 θ ) = 2 μ = 3 \cot( 2\theta) = 2\mu = \sqrt{3} .

So, 2 x = 30 , x = 1 5 2x=30, x=\boxed{15^\circ} .

Did the same!!!

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Try myne, a bit modified one

Partially Elastic

Md Zuhair - 3 years, 9 months ago

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Will surely try!!!! Nice question BTW.

A Former Brilliant Member - 3 years, 9 months ago

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@A Former Brilliant Member Thanks bro

Md Zuhair - 3 years, 9 months ago

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