Functional integral equations

Calculus Level 5

Let f \displaystyle f be an integrable function on [ a , b ] \left[ a, b \right] .

If a b f ( x ) d x = 12 \displaystyle \int_a^b f(x) \space dx = 12 , find a b a x f ( x ) f ( y ) d y d x \displaystyle \int_a^b \int_a^x f(x)f(y) \space dy dx .


The answer is 72.

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1 solution

Tom Engelsman
Sep 26, 2018

Let f ( x ) f(x) be an integrable function such that:

a b f ( x ) d x = F ( x ) a b = F ( b ) F ( a ) = 12. \int_{a}^{b} f(x) dx = F(x)|_{a}^{b} = F(b) - F(a) = 12.

Turning to our double integral now yields:

a b a x f ( x ) f ( y ) d y d x = a b f ( x ) [ a x f ( y ) d y ] d x = a b f ( x ) [ F ( x ) F ( a ) ] d x ; \int_{a}^{b} \int_{a}^{x} f(x)f(y) dy dx = \int_{a}^{b} f(x) [\int_{a}^{x} f(y) dy] dx = \int_{a}^{b} f(x)[F(x) - F(a)] dx;

or 1 2 F 2 ( x ) F ( a ) F ( x ) a b ; \frac{1}{2} \cdot F^{2}(x) - F(a)F(x)|_{a}^{b};

or 1 2 F 2 ( b ) 1 2 F 2 ( a ) F ( a ) F ( b ) + F 2 ( a ) ; \frac{1}{2}F^{2}(b) - \frac{1}{2}F^{2}(a) - F(a)F(b) + F^{2}(a);

or 1 2 ( F ( b ) F ( a ) ) 2 = 1 2 2 2 = 72 . \frac{1}{2} \cdot (F(b) - F(a))^2 = \frac{12^2}{2} = \boxed{72}.

@Tom Engelsman Why did you take f(x) to be a constant??? Can no other function satisfy the property???

Aaghaz Mahajan - 2 years, 5 months ago

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Hi, Aaghaz. It will work for any integrable function f(x) over [a,b], and I've amended my original solution accordingly. Hope this helps!

tom engelsman - 2 years, 5 months ago

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Ohhh I see Sir!!!! Thanks.........(Honestly, I am mad at myself for not figuring this out myself!!! XD )

Aaghaz Mahajan - 2 years, 5 months ago

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@Aaghaz Mahajan No prob! Honestly, I don't know how this one is considered a Level-5???

tom engelsman - 2 years, 5 months ago

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