Galileo's Tower!

Classical Mechanics Level 2

Galileo threw his ball from the top of the tower with velocity $v$ . And the ball reached the ground with velocity $3v$ . So what was the height of the tower?

\frac{8v^2}{g}

\frac{4v^2}{g}

\frac{9v^2}{2g}

\frac{3v^2}{2g}

3 solutions

Sravanth C.
Apr 21, 2015

Here initial velocity= v and final velocity = 3v.

Using the formula $v^{2}-u^{2}=2gs$

We get $(3v)^{2}-v^{2}=2gs$ .

Or, $9v^{2}-v^{2}=2gs$ .

Or, $8v^{2}=2gs$ .

Or, $\frac{8v^{2}}{2}=gh$ .

Or, $4v^{2}=gh$ .

Or, $\frac{4v^{2}}{g}=h$ .

Good Problem! :)

Mehul Arora - 6 years, 1 month ago

Great problem!

Sravanth C. - 6 years, 1 month ago

You are a G !

Muhammad Arifur Rahman - 6 years, 1 month ago

@Muhammad Arifur Rahman – Thank you!

Sravanth C. - 6 years, 1 month ago

You can make a little bit change in the problem and produce more problems. So, happy Problem Setting!!!

Muhammad Arifur Rahman - 6 years, 1 month ago

Yes. We could Add another thing and Replace one with a variable.

Mehul Arora - 6 years, 1 month ago

@Mehul Arora – So go ahead and share a new problem on your concept. Hopefully you give your best.

And don't forget to share the problem link with me.

Muhammad Arifur Rahman - 6 years, 1 month ago

jakasssssssss bro

Meet Charola - 6 years, 1 month ago

That was a good one

Dinesh Rathore - 6 years, 1 month ago

Nice solution you got ther bro!

Steven Sison - 6 years, 1 month ago

Yajnaseni Jena
Apr 28, 2015

FOLLOW THE EQUATIONS OF MOTION

Arian Tashakkor
Apr 28, 2015

I used the conservation law is and that gave me pretty much the same answer is that okay?

Galileo's Tower!

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