Driving you bananas

Let the price (in dollars) of an apple and a banana be denoted as $a$ and $b$ respectively.

Then from the first statement in the question as shown below, we can obtain the equation $a+b = 2.10$ .

Given that the total cost of an apple and a banana is $2.10

Similarly, from the second statement in the question as shown below, $a = b+2$ .

An apple costs 2 dollars more than a banana.

So we have two equations and with two variables: $a+b=2.10, a=b+2$ . Substituting the latter equation into the former equation gives

$(b+2) + b = 2.10 \Rightarrow 2b + 2 = 2.10 \Rightarrow 2b = 0.10 \Rightarrow b = 0.05$

Thus one banana costs $0.05, and so our answer is $\boxed{0.05}$ .

Double checking : When $b = 0.05$ , then $a = b+2 = 2 + 0.05 = 2.05$ . And this indeed the satisfy the equation $a+b= 2.10$ . So an apple costs $2.05 and a banana costs $0.05.

Suppose price of Banana = X According to equation, 2 + X + X = 2.10 Therefore, X = 0.05

most easiest way x+(x+2)=2.1 solve it and ans comes 0.05

Let the cost of banana be 'x' So the cost of Apple will be =x +2 Total cost is 2.10 So x + x+2 = 2x+ 2 = 2.10 Hence x=0.05 ,this is the cost of banana

cost of apple + cost of banana is = 2.10;

Let cost of banana = x;

Since apple costs $2 more than the banana, let the cost of apple = 2+x;

(2+x) + x = 2.10

2+2x=2.10

2x=0.10

x=0.05

Since cost of banana = x cost of banana = $0.05

Let x = the banana

x + (x+2) = 2.10 (x+2 is the Apple, costing $2 more than the x banana for a total of $2.10)

2 + 2x = 2.1 rearrange terms

2 + 2x/2 = 1.05 divide by 2 to get value of 1x, price of the banana

1 + x = 1.05

1.05 - 1 = x

Therefore, x (banana) = 0.05