Andrew, Bob, Catherine, David and Emma are discussing about rational numbers and recurring decimals.
Andrew: Infinite decimals cannot be rational numbers.
Bob: Finite decimals and recurring decimals are all rational numbers.
Catherine: Natural numbers can always be expressed in the form of a recurring decimal, while there exists an integer that cannot be expressed in that form.
David: Some recurring decimals cannot be expressed in the form of a fraction having both of its numerator and denominator as rational numbers.
Emma: Fractions that have their denominator as a power of 10 must be rational numbers.
Andrew has number 1 on his shirt, Bob has number 2, Catherine has number 4, David has number 8 and Emma has number 16.
Add up all of the numbers on the shirts of the people whose statement is correct.
Detail:
This problem is a part of <Grade 8 - Number Theory> series .
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Know that the definition of rational number is:
"A number that can be expressed as b a , where a and b are both integers. ( b = 0 )"
Andrew:
Counterexample: 0 . 3 3 3 3 3 ⋯ = 3 1 .
∴ F A L S E
Bob:
Let a n satisfy 0 < a i < 1 0 and a i ∈ N for all natural numbers i .
Finite decimal: 0 . a 1 a 2 a 3 a 4 ⋯ a n = 1 0 n a 1 a 2 a 3 a 4 ⋯ a n
Recurring decimal: 0 . a 1 a 2 a 3 a 4 ⋯ a n = 1 0 n − 1 a 1 a 2 a 3 a 4 ⋯ a n
∴ T R U E
Catherine:
Natural number n can always be expressed as ( n − 1 ) . 9 9 9 9 9 ⋯ .
Also, negative integer m can always be expressed as ( m + 1 ) . 9 9 9 9 9 ⋯ .
However, the integer 0 cannot be expressed as such form.
∴ T R U E
David:
Already proven wrong while solving Bob .
∴ F A L S E
Emma:
Counterexample: 1 0 2 2 = 0 . 0 1 4 1 4 2 1 3 5 ⋯ .
∴ F A L S E
From Andrew~Emma, we now know that only Bob and Catherine said a correct statement.
∴ 2 + 4 = 6 .