Is This Really a Big Product?

Algebra Level 1

n = 1 ( 1 1 n ) = ? \large{\displaystyle\prod_{n=1}^\infty \left(1-\dfrac{1}{n}\right) = \ ?}


Inspiration 1 and Inspiration 2 .


The answer is 0.000.

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8 solutions

Mehul Arora
Sep 26, 2015

n = 1 ( 1 1 n ) = ( 1 1 ) ( 1 1 2 ) ( 1 1 3 ) . . . . . . = 0 × 1 2 × 2 3 . . . . . = 0 \prod _{ n=1 }^{ \infty }{ (1-\frac { 1 }{ n } ) } =\quad (1-1)(1-\frac { 1 }{ 2 } )(1-\frac { 1 }{ 3 } )......\quad =\quad 0\quad \times \quad \frac { 1 }{ 2 } \quad \times \frac { 2 }{ 3 } .....\quad =0

@Nihar Mahajan it was very* n = 1 ( 1 1 n ) \large{\displaystyle\prod_{n=1}^\infty \left(1-\dfrac{1}{n}\right)} tough. :P

Aditya Kumar - 5 years, 8 months ago

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Still 23 people got scared and 6 people got it wrong. (till now) :P

Nihar Mahajan - 5 years, 8 months ago

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What?! I thought this would have 100% solvers.

Aditya Kumar - 5 years, 8 months ago

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@Aditya Kumar To be honest , to prove that a × 0 = 0 a R a \times 0 = 0 \ \forall a \in \mathbb{R} is not that obvious ;)

Nihar Mahajan - 5 years, 8 months ago

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@Nihar Mahajan Yes. I feel some people may not be knowing about the product symbol.

Aditya Kumar - 5 years, 8 months ago

@Aditya Kumar There may be some people who don't know that something real when multiplied by zero gives zero. xD

Nihar Mahajan - 5 years, 8 months ago

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@Nihar Mahajan Or thy are not getting inspired as you

A Former Brilliant Member - 5 years, 8 months ago

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@A Former Brilliant Member still this question has 25 points ! when i solved it , I got free 100 points ...

A Former Brilliant Member - 5 years, 8 months ago

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@A Former Brilliant Member Wow , So much lucky! You are so much rich. I wish I would be as lucky as you.

Nihar Mahajan - 5 years, 8 months ago

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@Nihar Mahajan Rich ? in terms of points I am behind you

A Former Brilliant Member - 5 years, 8 months ago

@Nihar Mahajan I got only 25. So sad. :'(

Aditya Kumar - 5 years, 8 months ago

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@Aditya Kumar Don't worry we have Chinmay Sangawadekar as the luckiest guy even in this world.He got 100 points free OMG! That was a miracle.What a luck!

Nihar Mahajan - 5 years, 8 months ago

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@Nihar Mahajan Then what about you ?

A Former Brilliant Member - 5 years, 8 months ago

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@A Former Brilliant Member If problem poster got some points for every problem he posted , I would have been a billionaire by now. -_-

Nihar Mahajan - 5 years, 8 months ago

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@Nihar Mahajan That depends

A Former Brilliant Member - 5 years, 8 months ago

@A Former Brilliant Member To whom exactly you are talking to? (Don't say myself)

Nihar Mahajan - 5 years, 8 months ago

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@Nihar Mahajan You !!! you got inspired that means you know the concept ...

A Former Brilliant Member - 5 years, 8 months ago

@Nihar Mahajan 1st inspirational problem is easy

A Former Brilliant Member - 5 years, 8 months ago

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@A Former Brilliant Member All problems are easy.

Nihar Mahajan - 5 years, 8 months ago

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@Nihar Mahajan Have you seen 'Hydra' ?

A Former Brilliant Member - 5 years, 8 months ago

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@A Former Brilliant Member Yeah , I have seen it.It is a is a genus of small, simple, fresh-water animals that possess radial symmetry. It has regenerative capacity and they reproduce by budding.

Nihar Mahajan - 5 years, 8 months ago

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@Nihar Mahajan Friend, I am talking about the 400 points problem..

A Former Brilliant Member - 5 years, 8 months ago

Nihar...can u explain me in detail about that..'pie' one thing ....what we call it??.....and what does this indicates??

A Former Brilliant Member - 5 years, 8 months ago

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@A Former Brilliant Member @Abhay Kumar "pi" is used for product. Just as "sigma" is used for sum, "pi" is used for product.

Aditya Kumar - 5 years, 8 months ago

@A Former Brilliant Member It means continued product.

Nihar Mahajan - 5 years, 8 months ago

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@Nihar Mahajan X=(10^21-9^17)/(10^14-9^11) find range of x

Naman Anand - 5 years, 7 months ago

@Nihar Mahajan Ok thanks...

A Former Brilliant Member - 5 years, 8 months ago

Level 2 : 935 views (100%)   494 attempts (53%)   387 solvers (41%)

Nihar Mahajan - 5 years, 8 months ago

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LOL ... a big LOL

A Former Brilliant Member - 5 years, 8 months ago

too much of inspiration...

A Former Brilliant Member - 5 years, 8 months ago

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Lol yeah :P

Mehul Arora - 5 years, 8 months ago

i just viewed the sol bcoz i didn't think that it waz sooo easy

nursery grade problem😜

Anuj Gupta - 5 years, 8 months ago

Can anyone compute the answer if sigma is present instead of pi.. i.e. if we have to calculate the sum instead of product??

Aditya Singh - 5 years, 6 months ago
Charles Rand
Sep 28, 2015

Since the first term is 0, it doesn't matter what the rest are because 0*any real number equals 0

You can't fool me! HaHa. Zero spoils everything

Akash Patalwanshi
Oct 22, 2015

Simply, if we simplify it, we get the first term as (1-1) that is 0. So the product will be again a 0

Adarsh Singh
Oct 8, 2015

Haw! It was not so easy :D

Ayush Patel
Oct 6, 2015

It's simple if (1-1)=0 therefore the whole term will be zero

Karan Jha
Sep 30, 2015

You gotta be kidding even a kid could have figured that outout

Arjen Vreugdenhil
Sep 29, 2015

The first factor is zero, so this is easy. But we also have n = 2 ( 1 1 n ) = 0... \prod_{n=2}^\infty \left(1-\frac1n\right) = 0... Right?

For n = 2 ( 1 1 n ) = 0... \prod_{n=2}^\infty \left(1-\frac1n\right) = 0... , the limiting value is 0

Raushan Sharma - 5 years, 8 months ago

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