To which whole number is the value below closest?
2 0 1 6 2 2 0 1 4 × 2 0 1 5 2
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Interesting problem! Can you explain that second step for me real quick though? I think I'm missing out on a rule I should know!
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2016^2 tends to infinity. So 1/(2016^2) tends to 0
second step is the simple expansion of (1 - 1/x)^2
2015/2016 = 2016/2016 - 1/2016 = 1 - 1/2016
How: (2 2014)/2016 = 2 and 2014/(2016 2016) = 0 can you please explain it?
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Close to 2 and close to 0. That's it.
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2x(2014/2016) close to 2*(1), so 2x(2014/2016) close to 2.
2014/(2016x2016) close to 2014/(2014x2016) close to 1/2016 close to 0 .
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But how: In response to Hassan Shahzad: 2x(2014/2016) = 2 and 2014/(2014x2016) =0
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@Hassan Shahzad – .
(2014/2016) close to 1, so 2x(2014/2016) close to 2x(1) = 2
2014/(2014x2016) = 1/2016 and 1/2016 close to 0,
so 2014/(2014x2016) =1/2016 close to 0.
@Hassan Shahzad – Approximate
Hahaha LOL
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We can write this as 2 0 1 4 ⋅ ( 2 0 1 6 2 0 1 5 ) 2 = 2 0 1 4 ⋅ ( 1 − 2 0 1 6 1 ) 2 .
Expanding out the squared term gives
2 0 1 4 ⋅ ( 1 − 2 ⋅ 2 0 1 6 1 + 2 0 1 6 2 1 ) = 2 0 1 4 − 2 ⋅ 2 0 1 6 2 0 1 4 + 2 0 1 4 ⋅ 2 0 1 6 2 1 ≈ 2 0 1 4 − 2 + 0 = 2 0 1 2 .