For any natural number x , let Υ ( x ) denote the sum of digits of x .
Find the number of all three digit numbers such that Υ ( Υ ( x ) ) = 5 .
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Oh! This property of 9 can really help to solve this type of question in short time.But I did it the long way solving taking cases:-(
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Yes i have seen this question..............................xD
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Where did you saw it?? @Vaibhav Prasad
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@Harsh Shrivastava – @Vaibhav Prasad RMO I think? S(S(2)) ??
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@Hrishik Mukherjee – And I have noticed a very beautiful result that number of three-digit numbers that satisfy Υ ( Υ ( x ) ) = 1 , 2 , 3 , . . . . . . , 8 are 100 .
@Vaibhav Prasad @Kalash Verma @Hrishik Mukherjee
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@Harsh Shrivastava – Nice observation!! :)
@Hrishik Mukherjee – Yep , I modified that problem!
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@Harsh Shrivastava – The name of your question suggests something =D
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@Hrishik Mukherjee – what??????
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@Harsh Shrivastava – Like .. If people know that a same type of question had appeared in RMO then Yes, They Have Seen It :)
" even I had to bash this question!"
What did you bashed??
The first three digit number whose sum of digits is 5 is 104. The next nuber is 113. We will find that difference between all these numbers comes to be 9 in each case. Using AP we can find the answer i.e. 900/9=100
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Hint: A natural number x leaves the same remainder when divided by 9 as the remainder which is left by dividing Υ ( x ) by 9 .