What is the mass of steam that should be passed through 60 g of water at 20 degree C, such that the final temperature is 40 degree C.(Take specific latent heat of steam as 2250 J g^-1)
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But i think it should be in grams
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No ,when you take specific heat , s in the L.H.S , you use the unit k g ⋅ K k J , then only the answer comes out to be 2.233 kg
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Hmmm.....ok thanks
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@Saksham Mittal – It's ok , just take m = 0 . 0 6 k g & s = 4 . 1 8 7 k g ⋅ K k J and solve to get the answer in " Kg".
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Using m ⋅ s ⋅ Δ T = M ⋅ ( 2 2 5 0 ) , the answer comes out to be M = 2 . 2 3 3 K g . You should mention to enter the nearest integer and in kg.