What is the mass of steam that should be passed through 60 g of water at 20 degree C, such that the final temperature is 40 degree C.(Take specific latent heat of steam as 2250 J g^-1)


The answer is 2.

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1 solution

Rishu Jaar
Nov 5, 2017

Using \text{Using} m s Δ T = M ( 2250 ) m\cdot s \cdot \Delta T = M \cdot (2250) , the answer comes out to be M = 2.233 K g \boxed{M= 2.233 Kg} . You should mention to enter the nearest integer and in kg.

But i think it should be in grams

Saksham Mittal - 3 years, 7 months ago

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No ,when you take specific heat , s s in the L.H.S , you use the unit k J k g K \dfrac{kJ}{kg\cdot K} , then only the answer comes out to be 2.233 kg

Rishu Jaar - 3 years, 7 months ago

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Hmmm.....ok thanks

Saksham Mittal - 3 years, 7 months ago

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@Saksham Mittal It's ok , just take m = 0.06 k g m=0.06 kg & s = 4.187 k J k g K s=4.187 \dfrac{kJ}{kg \cdot K} and solve to get the answer in " Kg".

Rishu Jaar - 3 years, 7 months ago

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