Here's the Second Harry Potter Question!

If the image is not clearly visible, No problem! All the details are given in the question

Harry's wand is threatened again, and this time Hermione must save it!

The wand was kept on a rough table (with friction coefficient 1) with one third of the total length on the table and the rest free. Assuming the mass of the rod is m kg, determine at what maximum angle rotated by the wand (shown by x in the image) will Hermione have to shout "arresto momenta" to save the wand from sliding on the table ?

Give your answer as the value of tan(x) .

Assumptions: Assume that "Arresto Momenta" stops the wand giving ample time to Hermione to go and handle the wand, thereby saving it from sliding on the table.


The answer is 0.5.

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2 solutions

Abhijeet Verma
Sep 28, 2015

Moderator note:

Can you explain why your equations describe the moment the wand loses contact? In other words, what distinguishes your constraints from a generic point in the movement of the wand?

@Kishore S Shenoy Check the solution. Since it was quite long,I posted it's snapshot.

Abhijeet Verma - 5 years, 8 months ago

One thing, I used θ \theta in place of x x as mentioned in the problem.

Abhijeet Verma - 5 years, 8 months ago

Challenge Master: In the solution above, I have used F r i c t i o n = μ s m a x × N o r m a l R e a c t i o n Friction\quad ={ \mu }_{ s\quad max }\times \quad Normal\quad Reaction , where μ s m a x { \mu }_{ s\quad max } is the maximum possible coefficien of static friction available, and hence it is the limiting case , after which the rod will start sliding.

Abhijeet Verma - 5 years, 8 months ago

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Great! In general, I would add more of your thought your process to your solutions, it makes them much more transparent to everyone else. Terrific problem and solution.

Brilliant Physics Staff - 5 years, 8 months ago

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Thanks! :)

Abhijeet Verma - 5 years, 8 months ago

@Abhijeet Verma I am sorry, I get it, I should never use ω = 0 \omega = 0 since it will slip at the limiting case and we have to find that case. I get my mistake. Thanks @Brilliant Physics and Abhijeet !

Kishore S. Shenoy - 5 years, 8 months ago

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No problem. Keep up the good work.

Brilliant Physics Staff - 5 years, 8 months ago

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OK Thanks!

Kishore S. Shenoy - 5 years, 8 months ago

Good work @Abhijeet Verma

Ayush Choubey - 5 years, 5 months ago
Pulkit Deshmukh
Aug 30, 2015

@AbhijeetVerma I hated the harry potter part

@Pulkit Deshmukh this is the way to tag a name

Abhijeet Verma - 5 years, 9 months ago

@Abhijeet Verma Can you explain how you got the answer?

Kishore S. Shenoy - 5 years, 8 months ago

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Surely, I will post my solution tomorrow. Btw, can you please post the solution to the problem collision gallore.

Abhijeet Verma - 5 years, 8 months ago

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I don't know. The solution will be highly complex in algebra right?

Kishore S. Shenoy - 5 years, 8 months ago

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@Kishore S. Shenoy Kishore S Shenoy You seem to be good in Mechanics You should try https://brilliant.org/problems/thats-why-i-like-physics/?group=sjTfEiwDY8IV&ref_id=963793

Pulkit Deshmukh - 5 years, 8 months ago

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@Pulkit Deshmukh And you try A very edgy problem!

Kishore S. Shenoy - 5 years, 8 months ago

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@Kishore S. Shenoy What do you mean by "when its centre of mass is in the horizontal line of the edge".I solved the rest of the part

Pulkit Deshmukh - 5 years, 8 months ago

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@Pulkit Deshmukh When the centre of mass of the cylinder is in line with the Edge horizontally. i.e. R dist traveled down by CM

Kishore S. Shenoy - 5 years, 8 months ago

@Pulkit Deshmukh Is my above solution right?

Kishore S. Shenoy - 5 years, 8 months ago

@Pulkit Deshmukh Is it a circle?

Kishore S. Shenoy - 5 years, 8 months ago

@Abhijeet Verma Try this question A very edgy problem!

Kishore S. Shenoy - 5 years, 8 months ago

Where is the first Harry Potter question?

Kishore S. Shenoy - 5 years, 8 months ago

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@Kishore S. Shenoy All questions posted by me are in the set Problems I Posted

Abhijeet Verma - 5 years, 8 months ago

Is this a solution?

Kishore S. Shenoy - 5 years, 8 months ago

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