Hexadecimal Clock (Problem 2 2 , Version 2 2 )

Computer Science Level 2

What's the time 23 : 59 23:59 in hexadecimal time?

Note: use a traditional clock but replace 10 , 11 , 12 10, 11, 12 with A , B , C A, B, C respectively.

17 : 3 D 17:3D 17 : 3 B 17:3B 17 : 3 C 17:3C 17 : 3 E 17:3E

Yajat Shamji by Yajat Shamji , 16, United Kingdom

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1 solution

Yajat Shamji
Jun 27, 2020

23 ÷ 16 = 1 23 \div 16 = 1

23 ( mod ( 16 ) ) = 7 23 (\text{mod} (16)) = 7

59 ÷ 6 = 3 59 \div 6 = 3

59 ( mod ( 16 ) ) = 11 → B 59 (\text{mod} (16)) = 11 \rightarrow B

Answer → 17 : 3 B \rightarrow 17:3B

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23 : 59 16 + 7 : 16 ⋅ 3 + 11 17 : 3 B \begin{aligned} 23 & : 59 \\ 16+7 & : 16\cdot3+11 \\ 17 & : 3B \end{aligned}

A Former Brilliant Member - 11 months, 2 weeks ago

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Great. How do you do the modulo function without spacing?

Yajat Shamji - 11 months, 2 weeks ago

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3 mod 4 3\text{mod}4 =3\text{mod}4

A Former Brilliant Member - 11 months, 2 weeks ago

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