Find the smallest root of the equation x 3 + 6 7 7 x 2 − 2 5 x − 1 6 9 2 5 = 0 .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
f ( x , y ) = ( 1 + x + y 2 ) ( 1 + y + x 2 ) = x 3 + x 2 ( 1 + y 2 ) + x ( 1 + y ) + y 3 + y 2 + y + 1
simply set y = 3 i to get first expression and y = − 2 6 to get the second.
The roots are − 1 − y , − − 1 − y , − 1 − y 2
Rohith buddy you have to change the terminology you have used
It's written above 'hidden symmetry'. We can easily see (by using calculator) that 5 and -5 satisfy the eqn. Then by using sum of roots>>>>> 5+(-5)+c= -677 => c= -677
Seems a lot easier solving the equation directly, instead of trying to 1) figure out what "...look for some homogeneity" means, and 2) actually finding that "homogeneity", whatever that means. That seems like a very difficult way to solve such an equation.
How does that method help find roots of an equation?
I felt the same, but @RohithMAthreya's solution also seems fine
Log in to reply
I'm just asking about how helpful it would be for other such polynomials.
I dont know how to solve cubic equations in a way other than first guessing a root and then solving a quadratic(which according to me is not a great method)
i was thinking if some symmetry could be established,one could do away with the trial and error.
as for what is easier, i can't say with certainty as to which method wins as it is perception dependent
this method would help find a solution to a class of cubic equations (very narrow,nevertheless) i am looking to broaden the class with some more work and this was only a precursor.
a person is most definitely free to solve the equation by itself but might also try to look around for some symmetry(which may seem abstract) if he has the time and patience
Log in to reply
and yes, homogeneity was a wrong term ( i was mistaken about what homogeneity was)
Log in to reply
probably "homogeneity" is the wrong word to use here, but it's nevertheless an interesting concept here.
Log in to reply
@Michael Mendrin – I am glad you think so :)
Problem Loading...
Note Loading...
Set Loading...
We could use 1 6 9 2 5 = 2 5 ∗ 6 7 7 Then the polynomial factorises to x 3 + 6 7 7 x 2 − 2 5 x − 2 5 ∗ 6 7 7 = ( x + 6 7 7 ) ( x + 5 ) ( x − 5 ) So smallest Root is − 6 7 7