All positive

Algebra Level 3

What is the smallest integer k k such that ( k 2 ) x 2 + 8 x + k + 4 (k-2) x^2 + 8x + k + 4 is positive for all real x x ?

3 5 2 1

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1 solution

Rishu Jaar
Nov 4, 2017

For a Quadratic equation to be always positive, coefficient of x 2 x^2 must be positive and its discriminant must be strictly negative.

k 2 > 0 i n e q . n ( 1 ) \large \color{#20A900}{\implies k - 2 > 0}\hspace{1cm}\ldots ineq.^n(1) 64 4 ( k 2 ) ( k + 4 ) < 0 i n e q . n ( 2 ) \large \color{#3D99F6}{\implies 64 - 4(k-2)(k+4) < 0} \hspace{1cm}\ldots ineq.^n(2) Simultaneously solving both inequations gives \rightarrow k ( 4 , ) \large \color{#D61F06}{\implies k \in (4,\infty)} Thus the smallest integer value is k = 5 \large\color{#69047E}{\boxed{k=5}}

Relevant Wikis : - Quadratic expression - Parabola

Could you please prove that discriminant must be strictly negative for a polynomial to be positive?

Aman thegreat - 3 years, 7 months ago

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A proof is quite simple, btw i said that For a quadratic expression to be always positive, it must have a negative discriminant and a positive coefficient of x 2 x^2 .

Rishu Jaar - 3 years, 7 months ago

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Ok please prove it

Aman thegreat - 3 years, 7 months ago

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@Rishu Jaar I hope all your basic doubts are cleared after reading them and i have updated my solution. Thank you.

Rishu Jaar - 3 years, 7 months ago

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