Hot Question on Cool Topic of Power #2

Algebra Level 4

( 1 ) ( 2 ) ( 3 ) ( 4 ) = ? \huge \color{#3D99F6}{(-1)^{(-2)^{(-3)^{(-4)}}}= \ ?}


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1 Irrational Number Not a Real Number -1 Rational Number other than {1,-1}

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1 solution

Dawar Husain
May 19, 2015

1 2 3 4 \large{-1^{-2^{-3^{-4}}}} = 1 2 ( 1 3 4 ) \large{=-1^{-2^{ \left( \frac{1}{-3^{4}}\right)}}} = 1 2 ( 1 81 ) \large{=-1^{-2^{ \left( \frac{1}{81}\right)}}} Not a real no. \implies \text{Not a real no.}

Wrong. Where's your parentheses? You're wrong in the first line itself. You failed to justify why it's a non real number from 3rd step to 4th step.

Pi Han Goh - 6 years ago

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Can you provide a solution for this problem? After the (-1)^\sqrt[81]{-2} , I didn't manage to go any further.

Nowras Otmen - 5 years, 8 months ago

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Show that the (-2)^(1/81) is an irrational number.

Pi Han Goh - 5 years, 8 months ago

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@Pi Han Goh Sure, it is irrational, but since its (-1) that we are dealing with, shouldn't the only possible answers be 1 or -1? The problem I have it's that it isn't possible to define if 2^1/81 is even or odd. So, as far I can see, the answer would be a real number, but an undefined one.

Nowras Otmen - 5 years, 8 months ago

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@Nowras Otmen Whoops. I meant to say that we should prove that it's not a real number. With (-2)^(1/81) being a complex number, then so is (-1)^( (-2)^(1/81) ).

Pi Han Goh - 5 years, 8 months ago

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@Pi Han Goh Sorry to be bothering you again, but isn't 2 81 \sqrt[81]{-2} a real number? Since 81 is odd, it shouldn't matter if the radicand is positive or negative, it will be real nonetheless, right? (e.g. 8 3 \sqrt[3]{-8} ) Also, I have yet to study complex numbers in depth, so I apologize in case I commit any mistakes regarding that subject.

Nowras Otmen - 5 years, 8 months ago

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@Nowras Otmen Not it's not real. y = x^(1/81) is only defined (real) for x > 0. so with -2 < 0, then (-2)^(1/81) is not real.

Pi Han Goh - 5 years, 8 months ago

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@Pi Han Goh Ok, thank you very much.

Nowras Otmen - 5 years, 8 months ago

But -2^1/81. Could be a negative yet a very small number. For this whole expression to be unreal no. the result obtained in -2^... should be a no. with 1 as the numerator and an odd no. as the denominator.

Mukul Sharma - 6 years ago

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I think 1 is the correct answer

Riddhesh Deshmukh - 5 years, 8 months ago

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