How to evaluate power towers?

Logic Level 3

2 2 2 n number of ’s 2 = 2 2 2 2 2 \Large 2 \; \underbrace{\square \; 2 \; \square \; \cdots \; \square \; 2 \; \square}_{n \text{ number of }\square\text{'s}} \; 2 = 2^{2^{2^{2^2}}}

What is the minimum value of positive integer n n such that we can fill in the boxes above with the four mathematical operators ( + , , × , ÷ +, -, \times , \div ) and the equation holds true?

Note : Order of operations (BODMAS) applied.

Bonus : What would the answer be if we were to find the maximum value of integer n n ?


The answer is 65535.

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1 solution

Alekhya China
Jul 11, 2016

among the operations +,-, ,/ the value can increase in the greatest rate by using * in all places now we need to calculate how many * in 2 2 2 ........*2=2^65536. so the no of * will be 65535. want explanation?

Want explanation? Yes

Pi Han Goh - 4 years, 11 months ago

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it's very simple-if we evaluate the right hand tower then it becomes2^65536.hence in left hand side 65536 2's are to be multiplied.so the no of * signs are 65535.did you get it?

ALEKHYA CHINA - 4 years, 11 months ago

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Yes! Yeeees! Thanks

Pi Han Goh - 4 years, 11 months ago

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@Pi Han Goh are you a Olympiad aspiarant mr.Pi Han Goh

ALEKHYA CHINA - 4 years, 11 months ago

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@Alekhya China haha, no no.

Pi Han Goh - 4 years, 11 months ago

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@Pi Han Goh can you tell me some good names of problem books of number theory ?

ALEKHYA CHINA - 4 years, 11 months ago

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@Alekhya China This one

Pi Han Goh - 4 years, 11 months ago

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