Hybridization

Chemistry Level 2

What is the hybridization of nitrogen in the compound above?

\text{sp}^3

\text{sp}^2

\text{sp}^4\text{d}

\text{sp}

3 solutions

Raj Rajput
Feb 4, 2016

But why not sp3?

lemon juice lemon juice - 5 years, 4 months ago

Since the lone pair of nitrogen is in conjugation with ring and it can delocalize over ring we does not consider it while finding hybridization

That's why We remains with 3 sigma bonds (2 with hydrogen and 1 with ring )

And hence hybridization is sp2

RAJAT PATIL - 5 years, 4 months ago

Thanks very much for your explanation😄

lemon juice lemon juice - 5 years, 4 months ago

Moreover double bond is counted as one during calculating hybridisation.

RAJ RAJPUT - 5 years, 4 months ago

If it weRe sp3,the ResonAnce would not not hAve been possible heRe.but we know thAt pyRidine shows ResonAnce. ThAnk ew

ali anwar rocker - 5 years, 4 months ago

Its aniline @ali anwar rocker :)

RAJ RAJPUT - 5 years, 4 months ago

@Raj Rajput – Ohh i could not see the nitRogen Atom well.i Apologize and thank you so much buddy

ali anwar rocker - 5 years, 4 months ago

Nice! Another shortcut is that we need to see that to how many atoms (elements) the atom (N) is bonded:

1) bonded to 2 atoms} sp

2) bonded to 3 atoms} sp2

3) bonded to 4 atoms} sp3

etc...

Rajdeep Bharati - 5 years ago

Sunil Mehta
Nov 26, 2016

due to resonance partial double bond character comes and hence hybridization becomes sp2

Ali Anwar Rocker
Feb 8, 2016

The lone pAiR of nitRogen in aniline tAkes pARt in ResonAnce And gets delocAlised. And ResonAnce is pResent in only plAnAR compounds.so hybRidisAtion of nitRogen heRe,is sp2

Hybridization

3 solutions

0 pending reports