If f ( x ) = a ln ∣ x ∣ + b x 2 + x has its extremum values at x = − 1 and x = 2 , then which option is correct?
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@Sambhrant Sachan , it is unnecessary to enter text in LaTex. It is difficult and the text does not flow with page width. And most importantly it is not the standard practice of Brilliant website. Since lo g , tan , cos are functions please put a backslash "\" in front, as you do for \frac. Let us see the differences a log |x| a l o g ∣ x ∣ . Notice that all the text are in italic and stick together though I allow spaces. But a\log|x| a lo g ∣ x ∣ , only a and x , constant and variable are in italic, lo g , a function is not in italic (check tan and cos above). Also there are spaces before and after lo g automatically placed in. You must allow a space between function and argument, for example: \tanx \tanx is an error but \tan x tan x is okay.
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I changed the text , but i don't see anything wrong with the functions . i always put a backslash before a function . For e.g i have written alog|x| as a\log{|x|} : a lo g ∣ x ∣ and tanx as \tan{x} : tan x , which works perfectly.
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I have changed a few of your problems for you. That was why, I mentioned this here. Also Brilliant staff go round editing problems. I was appointed as a moderator.
Check out this one , I changed the cot x and tan x , and this one , I changed the tan and cos .
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@Chew-Seong Cheong – These are not my problems. The problems are posted by 'subhamkar Ayare' .
@Sambhrant Sachan @Chew-Seong Cheong
I will take care henceforth (and correct/modify if any mess is left behind in previously posted problems). Thank you for informing.
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Thanks for understanding. All for the good of Brilliant. Wishing you a happy 2017.
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f ( x ) f ′ ( x ) = a lo g ∣ x ∣ + b x 2 + x = ∣ x ∣ a × ∣ x ∣ x + 2 b x + 1
Put f ′ ( x ) = 0 for extremum values
x a + 2 b x + 1 2 b x 2 + x + a = 0 = 0
− 1 and 2 are roots of this quadratic equation.
− 1 + 2 = − 2 b 1 and − 1 × 2 = 2 b a
b = − 2 1 and a = 2