I'm on my limit!

Calculus Level 1

Shopsuey wants to buy some loaves of bread. When the baker asked him how many loaves he would take, Shopsuey gave him the following paper. How many loaves he took?

infinite 9 1 6 0

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2 solutions

Why does the last line say lim x 3 6 \displaystyle\lim{x\to3}\boxed{\approx}6 ?

Omkar Kulkarni - 5 years, 11 months ago

or we can use the L'Hospital Rule.

Trishit Chandra - 6 years, 4 months ago

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Sure, but why should we make it more difficult?

Júlio Vinicius Rodrigues Miguel - 6 years, 4 months ago

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using L'hospital is more easier to me than factorizing something. Because in this rule we just have to differentiate and nothing else.

Trishit Chandra - 6 years, 4 months ago

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@Trishit Chandra Could you post a solution using the L'hospital Rule? Thank you.

Júlio Vinicius Rodrigues Miguel - 6 years, 4 months ago
Caleb Townsend
Feb 27, 2015

Since the numerator and denominator both approach 0 , 0, by L'Hôpital's rule, lim x 3 x 2 9 x 3 = lim x 3 2 x = 6 . \lim_{x\to 3} \frac{x^2 - 9}{x - 3} = \lim_{x \to 3} 2x = \boxed{6}. While this may look neat, it takes more than twice as long to verify the limits are both 0 0 and then differentiate and evaluate, than it does to simply factor it, since it is of the form a 2 b 2 . a^2 - b^2.

In other words, it is faster to factor since minimal thought is required; ( x 2 9 ) (x^2 - 9) can be factored in a split second if you know that 9 = 3 2 . 9 = 3^2. If you use differentiation, though, it becomes a process of 3 3 separate evaluations, so even if you can differentiate super-fast, it still requires 2 2 more evaluations than the factoring method.

Caleb Townsend - 6 years, 3 months ago

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