Probability of Transcendental

If we pick a number uniformly at random from [ 0 , 1 ] [0,1] , what is the probability that the number is a transcendental number ?


Inspiration, see solution .

0 0 1 3 \frac{1}{3} 1 1 1 2 \frac{1}{2}

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1 solution

Algebraic numbers and transcendental numbers form a partition of the interval [ 0 , 1 ] [0,1] . As the algebraic numbers are countable, they have a measure of 0 0 , and since the respective measures of the algebraic and transcendental numbers are complementary and add to 1 1 the measure of transcendental numbers on the given interval is 1 1 , i.e., the probability that a number picked at random on [ 0 , 1 ] [0,1] is transcendental is 1 \boxed{1} .

Doesn't "probability of picking a transcendental in [ 0 , 1 ] [0,1] is 1 1 " mean that picking of a transcendental, in this case, is a sure event (which I suppose, is not !) ? I am perplexed.

Venkata Karthik Bandaru - 5 years, 4 months ago

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"Probability of 1" is different from "surely happens".

Ivan Koswara - 5 years, 4 months ago

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Courtesy: Wikipedia

Probability is the measure of the likelihood that an event will occur.[1] Probability is quantified as a number between 0 and 1 (where 0 indicates impossibility and 1 indicates certainty)

I see that the above statement complies with "Probability of 1" meaning "surely happens".

Venkata Karthik Bandaru - 5 years, 4 months ago

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@Venkata Karthik Bandaru That notion is only correct for finite event space. See the concept of almost surely .

Ivan Koswara - 5 years, 4 months ago

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@Ivan Koswara Woah, now I get it. Thanks !

Venkata Karthik Bandaru - 5 years, 4 months ago

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