Integrate using what!

Calculus Level 5

0 x 9 e x ( 11 e x 11 e 2 x + e 3 x 1 ) ( e x + 1 ) 5 d x \large{\displaystyle \int^{\infty}_{0} x^{9} \frac{e^{x}(11e^x-11e^{2x}+e^{3x}-1)}{(e^x+1)^{5}} dx}

The value of above integral is equal to A B π C \large{\frac{A}{B} \pi^{C}} where A , B , C Z A,B,C\in \mathbb Z and A , B A,B are co-prime integers.

Find A × ( B + C ) A\times(B+C)

Original problem


The answer is 2604.

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1 solution

Tanishq Varshney
Oct 8, 2015

@Upanshu Gupta plz check it out

Tanishq Varshney - 5 years, 8 months ago

@Tanishq Varshney the mistake you made in realizing that Γ ( n ) = ( n + 1 ) ! \Gamma(n) =(n+1)! is wrong so the integral should equal 9 ! 9! not Γ ( 7 ) \Gamma(7) but Γ ( 10 ) \Gamma(10) equalling 9!

Kunal Gupta - 5 years, 8 months ago

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@Tanishq Varshney rest I did the same!

Kunal Gupta - 5 years, 8 months ago

It's ( n 1 ) ! (n-1)! my friend

Tanishq Varshney - 5 years, 8 months ago

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@Tanishq Varshney you know it's confusing!! but I even wolfram alpha(ed) the integral: 0 x 9 e x d x = 9 ! = 362880 \int_0^{\infty}x^{9}e^{-x}dx =9! =362880

Kunal Gupta - 5 years, 8 months ago

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@Kunal Gupta Ya u are right , I got screwed up. @Calvin Lin sir plz change the answer

Tanishq Varshney - 5 years, 8 months ago

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@Tanishq Varshney @Tanishq Varshney finally ! victory!! :P

Kunal Gupta - 5 years, 8 months ago

@Tanishq Varshney @Tanishq Varshney btw my name's changed (3 years back) to Kunal Gupta but I can't change it on Brilliant

Kunal Gupta - 5 years, 8 months ago

@Tanishq Varshney I think you should ask @Calvin Lin to change the answer to 2604 2604

Kunal Gupta - 5 years, 8 months ago

Shouldn't you update the solution likewise?

Kartik Sharma - 5 years, 8 months ago

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yup, i will

Tanishq Varshney - 5 years, 8 months ago

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