Is It Correct that Sum Of the All Numbers To Infinite = -1
True or False?
1 + 2 + 4 + 8 + ⋯ + 2 n + ⋯ = − 1
(Use the standard system of arithmetic.)
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1 solution
I can't understand how you got +ve = -ve?
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The question is the sum of all even numbers like 2^n form is equal to -1 There is virgate of number if you multiply by splitting the number in sort of substraction as 1 is splite as (2-1) then what it gives by multipling the terms will be Positive and negative. also this could be only in case of even numbers to be an equality.
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I can't understnad what you are saying. Will you write it in equations.
I'm sorry but this is wrong. The explanation is very simple actually;the L.H.S is the sum of positive numbers only,so it will never equal a negative number.
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do you have better solution that sum of +ve numbers equal to -1???
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I'm saying that the statement 1 + 2 + 4 + 8 + ⋯ + 2 n = − 1 is wrong. Therefore, there isn't any solution at all to show that this statement is true.I was simply proving how it was wrong in my first comment,not how it was right.
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@Abdur Rehman Zahid – oh,sorry for my ignorance you are absolutely right its wrong statement, but i just clarify that it would have a solution that maybe errored or perhaps wrong .
Let the observe ,clear that its not sum of all the numbers i.e. natural numbers instead it is about even numbers only.
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I did not say that it was the sum of all numbers;I simply said that it was the sum of positive numbers (which can never equal a negative number)
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@Abdur Rehman Zahid – yes,but i didnt say you are wrong instead i stressing on that point out on which i need to clarify.
H e r e , I t − I s H o w I t s C o r r e c t a b l e . . .
1 + 2 + 4 + 8 + 1 6 + . . . = 1 . ( 1 + 2 + 4 + 8 . . . )
1 + 2 + 4 + 8 + . . . = ( 2 − 1 ) . ( 1 + 2 + 4 + 8 + . . . )
1 + 2 + 4 + 8 + . . . = 2 + 4 + 8 + 1 6 − 1 − 2 − 4 − 8 − 1 6
1 + 2 + 4 + 8 + . . . = − 1