Is This Another Factorials Identity?

True or false :

( n ! ) ! = n ! × ( n ! 1 ) ! \Large (n!)! = n! \times (n!-1)!

True False

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4 solutions

Let n ! = m n!=m . The expression is equivalent to m ! = m ( m 1 ) ! m!=m(m-1)! which is true.

I have made the substitution just to make it more clear.

Yes! It is just that simple!

Chung Kevin - 5 years, 2 months ago

Same method !

Chirayu Bhardwaj - 5 years, 2 months ago

It's not true for n=0,1 so please make it clear

Shiv Kumar - 5 years, 2 months ago

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Why so, ( 0 ! ) ! = 0 ! × ( 0 ! 1 ) ! (0!)! = 0! × (0!-1)!
1 = 1 × ( 1 1 ) ! 1 = 1 ×(1-1)!
1 = 1 × 0 ! 1 = 1×0!
1 = 1 × 1 1=1×1
1 = 1 1=1 .

Ashish Menon - 5 years, 2 months ago

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I can't see last factorial symbol. Your solution is right. Thanks for clarifying

Shiv Kumar - 5 years, 2 months ago

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@Shiv Kumar Which last factorial? Thanks :-)

Ashish Menon - 5 years, 2 months ago

It is true. 0!=1.

A Former Brilliant Member - 5 years, 2 months ago
Suzie Nguyen
Jun 4, 2021

I guessed ;))

Aiman Aimn
Mar 23, 2016

n! Exactly

Calvin Rieder
Mar 23, 2016

Let n!=x

x! = x*(x-1)!

x! = x*(x!/x)

x! = x!

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