It Always Boils Down to a Number

Algebra Level 1

If x = 2 3 + 7 x = \frac{2}{3+\sqrt7} , then find ( x 3 ) 2 (x-3)^2 .


The answer is 7.

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2 solutions

Ameya Salankar
Jun 8, 2014

When we rationalise x x , we get -

2 3 + 7 × 3 7 3 7 = 3 7 \frac{2}{3+\sqrt{7}} \times \frac{3-\sqrt{7}}{3-\sqrt{7}} = 3-\sqrt{7} .

Substituting x x , we get,

( x 3 ) 2 = ( 3 7 3 ) 2 = ( 7 ) 2 = 7 (x-3)^2 = (3-\sqrt{7}-3)^2 = (-\sqrt{7})^2 = \boxed{7} .

Nicely done. To be honest, I solved this in 4 seconds! Too much of this done in 9th :P

Krishna Ar - 7 years ago

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Same. Great minds think alike. :D

Finn Hulse - 7 years ago

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Thank you :D

Krishna Ar - 7 years ago

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@Krishna Ar @Krishna Ar , how come you are in 10th & still 14?

Ameya Salankar - 7 years ago

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@Ameya Salankar Hey , I was born in Nov/99. FYI, There are people who were born even in May 2000 in my class. SO, they've just turned 14 and I'm like 14.5 years old.

Krishna Ar - 7 years ago

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@Krishna Ar @Krishna Ar , interesting! This means there are people in your class that should have been 8th pass now but are 2 years ahead! Wow!

Ameya Salankar - 7 years ago

@Krishna Ar When i passed 10th i was also 14.5 but you are still intelligent more

Nitish Kumar - 5 years, 10 months ago

@Krishna Ar What is 9th?

Mardokay Mosazghi - 7 years ago

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He refers to the 9th grade @Mardokay Mosazghi . In India, we call it 9 th 9^{\text{th}} standard.

Ameya Salankar - 7 years ago

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I know that.

Ameya Salankar - 7 years ago

How u solve this,can u explain basic rule of rationalise

Amarsinh Patil - 7 years ago

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@Amarsinh Patil , rationalisation means making the denominator a rational number. We usually multiply both - numerator & denominator, by the conjugate - that is, changing the sign in the middle of the same term.

Ameya Salankar - 7 years ago

wow its so easy bt i did nt know it ...

Can somebody explain me how this was rationalised......

Satvik Raj - 7 years ago

Krishna pls tell me the solution

Faryal Faizan - 7 years ago

Nyc solution

Chinmoyranjan Giri - 7 years ago

good work !

Rikita Rockey - 6 years, 11 months ago

Nicely trick

santosh h - 6 years, 11 months ago

x(3 + sq.rt 7)=2 so 3x + x(sq.rt 7) = 2 ; so 9x sqd + 7 X sqd = 4 i.e 16 X sqd =4

so 4X=2 x=0.5 ; x-3 = -2.5; (x-3)sqd = (-2.5) sqd = 6.25

David Vincent - 5 years, 10 months ago

from sympy import sqrt from sympy.simplify.simplify import rad_rationalize from sympy import symbols

rad_rationalize(2,3+sqrt(7))

-> yields (-6 + 2*sqrt(7), -2)

x=symbols('x') (((-1/2.) (-6 + 2 sqrt(7))-3)**2).simplify()

-> yields 7.00000000000000

Yes, it took me longer than four seconds.

Bill Bell - 7 years ago

Write 2=(3+7^1/2)(3-7^1/2) and then its simple algebra. :)

Amrita Pritam - 6 years, 11 months ago
Josh Banister
Jan 20, 2015

Using 2 < 7 < 3 2 < \sqrt{7} < 3 , It is simple to deduce that 2 6 < 2 3 + 7 < 2 5 \frac{2}{6} < \frac{2}{3 + \sqrt{7}} < \frac{2}{5} . Hence, 8 3 < x 3 < 13 5 \frac{-8}{3} < x-3 < \frac{-13}{5} and squaring this gives 8 > 64 9 > ( x 3 ) 2 > 169 25 > 6 8 > \frac{64}{9} > (x-3)^2 > \frac{169}{25} > 6 Since the answer has to be an integer between 6 and 8, ( x 3 ) 2 = 7 (x-3)^2 = 7

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