It May Weigh Less

Besides the applied $14 \text{ N}$ , there is another external force due to the weight of the hanging $3 \text{ kg}$ block, which is $F_1 = 3 g \text{ N}$ , where $g \approx 10 \text{ ms}^{-2}$ is the acceleration due to gravity. Therefore, the downward acceleration $a_1$ due to $F_1$ is given by $F_1 = (3+5)a_1 = 3 g$ $\implies a_1 \approx \frac {30}8$ $= 3.75 \text{ ms}^{-2}$ . The upward acceleration $a$ due to the $14 \text{ N}$ force is $(3+5)a = 14$ $\implies a = \frac {14}8$ $= 1.75 \text{ ms}^{-2}$ . Since the downward acceleration $a_1$ is much larger than the upward acceleration $a$ , assuming insignificant friction between the $5 \text{ kg}$ block and the table top and between the rope and pulley, and the rope is light weight, the $3 \text{ kg}$ block will move down .