JEE Inorganic (1)!
Xenon is reacted with fluorine in the ratio 1:20 to give a compound A.
A Is Completely Hydrolysed to give an explosive and hygroscopic solid B.
B Is reacted with Aqueous solution of NaOH to give salt(C) of an acid.
Now Is C Is allowed to disproportionate in basic medium to obtain a number of products.
Out of these number of products two products are derivatives of xenon.
Find the Oxidation number of xenon in the above obtained 2 products.
(for finding oxidation state take that compound of xenon in which its oxidation state is higher)
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1 solution
The first reaction is the formation of X e F 6 followed by its hydrolyses to give X e O 3 .
When dissolved in a basic medium the salt N a H X e O 4 is formed. (Note that this is the only salt series in existence for this anion)
This salt disproportionates to form Xenon gas, oxygen and a perxenate salt.
4 N a H X e O 4 ⟶ N a 4 X e O 6 + 3 X e + 4 O 2 + 2 H 2 O
The oxidation states of the products are 0 and 8 for X e and N a 4 X e O 6 respectively.