JEE maths#11

$\tan^{-1} \frac{( \cos 2\alpha \sec 2\beta + \cos 2\beta \sec 2\alpha) }{\lambda} = \tan^{-1}(\tan^{2}( \alpha + \beta) \tan^{2}( \alpha - \beta) + 1 )$

Find the value of $\lambda$ in the equation above.

• For more JEE problems try my set 1
• For KVPY practice questions try my set 2