Jump !

S=height

$S =\dfrac{1}{2} \cdot g \cdot t^2$

$S = \dfrac{1}{2} \cdot 10 \cdot 1^2$

$S = \boxed{5}$

The general formula for the distance traveled in the time $t$ by an accelerated object is $y=v_ot+\dfrac{1}{2}at^2$ . Here $v_o=0$ since you simply jump from rest, and the acceleration is $a=g=10$ . Hence, we have $y=\dfrac{1}{2}gt^2$ . So

$y=\dfrac{1}{2}(10)(1^2)=$ $\color{#D61F06}\boxed{5}$

$t = \sqrt\frac{2h}{g} = 1s \Rightarrow h = 5m$ .