1 × 4 × 7 1 + 4 × 7 × 1 0 1 + 7 × 1 0 × 1 3 1 + ⋯ + 1 9 × 2 2 × 2 5 1 = b a
The equation above holds true for positive coprime integers a and b . Find a + b .
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@Ivan Richmond Jumawan , you should use \times for × and not x x .
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Thanks for that, I will next time. :)
Btw, Mr. Cheong, I know you have great knowledge when it comes to math, can I ask you to be my mentor?
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You can post discussion on Brilliant.org
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@Chew-Seong Cheong – Ok. I will. Haven't tried it yet. thanks.
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@Ir J – Can add me on Facebook Chew-Seong Cheong if you want.
1 × 4 × 7 1 + 4 × 7 × 1 0 1 + 7 × 1 0 × 1 3 1 + ⋯ + 1 9 × 2 2 × 2 5 1
= 6 1 ( ( 1 × 4 1 − 4 × 7 1 ) + ( 4 × 7 1 − 7 × 1 0 1 ) + . . . + ( 1 9 × 2 2 1 − 2 2 × 2 5 1 ) )
= 1 × 4 × 6 1 − 2 2 × 2 5 × 6 1
= 2 2 0 0 9 1
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S = 1 × 4 × 7 1 + 4 × 7 × 1 0 1 + 7 × 1 0 × 1 3 1 + ⋯ + 1 9 × 2 2 × 2 5 1 = 1 8 1 ( 1 1 − 4 2 + 7 1 + 4 1 − 7 2 + 1 0 1 + 7 1 − 1 0 2 + 1 3 1 + ⋯ + 1 9 1 − 2 2 2 + 2 5 1 ) = 1 8 1 ( 1 − 4 1 − 2 2 1 + 2 5 1 ) = 2 2 0 0 9 1 By partial fraction decomposition
Therefore, a + b = 9 1 + 2 2 0 0 = 2 2 9 1 .