8
sin
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cos
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π
+
4
sin
1
0
π
+
1
=
α
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α
+
α
+
α
+
⋱
1
1
1
Find
α
.
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Looks like your first latex soln.!Great job!!
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Learning to use latex.. :) . Are there any flaws in the solution that made you conclude this? (just asking)
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When writing text use this format
\text{...}
otherwise the text will appear in italics.For eg.,
H
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(italics) and
Hi Rishabh
.You can see the difference!Use \ before sin,and your solutions will become flawless!btw(+1)
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4 × 2 sin 1 0 π cos 5 π + 4 sin 1 0 π + 1 = 4 ( sin 1 0 3 π − sin 1 0 π ) + 4 sin 1 0 π + 1 = 4 sin 1 0 3 π + 1 = 4 ( 4 5 + 1 ) + 1 = 5 + 2 Now , 5 + 2 = α + 5 + 2 1 α = ( 5 + 2 ) − ( 5 + 2 1 ) ⇒ α = 4