( x , y ) → ( 1 , 1 ) lim x − y x 2 y − y 2 x = ?
Note: Enter 999 if the limit does not exist or is not defined.
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Should not (x,y) → (1,1).
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Oops! Well... I've mistaken it as (0,0). Thanks.. I have edited the problem now
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Well it has cost me good 100 points.. :D ......BTW no problem..
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@Rishabh Jain – Thanks. Those who answered 0 have been marked correct.
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( x , y ) → ( 1 , 1 ) lim x − y x 2 y − y 2 x = ( x , y ) → ( 1 , 1 ) lim x − y x y ( x − y ) = ( x , y ) → ( 1 , 1 ) lim x − y x y ( x − y ) ( x + y ) = ( x , y ) → ( 1 , 1 ) lim x y ( x + y ) = 1 × 1 × ( 1 + 1 ) = 0 2