If V is a vector space of dimension 100, and W 1 and W 2 are vector sub spaces of V of dimension 59 and 63 respectively, then the maximum possible dimension of W 1 + W 2 is:
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i showed that dim(W1+W2)<= minimum{ dimV, dimW1+dimW2} So minimum =100
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but how did you show that?
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As dim[w1+w2] = dim[w1]+dim[w2]-dim[w1 /\ w2] , so dim[w1]<= dim[w1+w2]<= dim[w1]+dim[w2] and dim[w2]<=dim[w1+w2]<=dim[V] then we imply that max{dim[w1],dim[w2]}<=dim[w1+w2]<=min{dim[V],dim[w1]+dim[w2]}....
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@Amar Mavi – I don't get it. It seems to me that dim ( W 1 + W 2 ) ≤ min ( dim ( V ) , dim ( W 1 ) + dim ( W 2 ) ) merely implies that dim ( W 1 + W 2 ) ≤ 1 0 0 . You need to show that 100 is attained; that's what I'm trying to do in my solution.
@Amar Mavi – Is there a way you can write this up in LaTeX?
Plus I love the picture of Cayley, there is a bust of him in my unis mathematics department.
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Let v 1 , . . , v 1 0 0 be a basis of V . If W 1 = s p a n ( v 1 , . . , v 5 9 ) and W 2 = s p a n ( v 3 8 , . . v 1 0 0 ) , then W 1 + W 2 = V so dim ( W 1 + W 2 ) = dim ( V ) = 1 0 0 .