Can You Deduce The Distance Of The Sun From The Earth?

Time $=8\frac{1}{2} = \frac{17}{2} min = \frac{17}{2}\times 60 = 17\times 30 = 510$ sec.

So, we know, Speed of light $=3\times 10^{8}$ m/s.

Now, we know that,

Distance=Speed $\times$ Time $\implies d=3\times 10^{8} \times 510 = 1530 \times 10^{8} = 1.53\times 10^{11} = \boxed{1.53E+11}$

Let $d$ be the distance in meters between the sun and earth.

Given, $v$ = speed of light = $3 \times 10^{8}$ m/s

$t$ = time for the light to travel from sun to earth = $8.5$ minutes = $8.5 \times 60$ seconds = $510$ seconds.

Using the equation,

$d = v \times t$

we get

$d = 3 \times 10^{8} \times 510$

$d = 1.53 \times 10^{11}$ meters

That's the answer!

We know : Distance = Speed x Time

$Time (in seconds) = Time (in minutes) * 60 = 8.5 * 60 = \boxed{ 510s}$

Putting given values we get : * $Distance = 3*10^{8}*510s = 1.53*10^{11}s$ *

speed of light = 3 x 10^8 time taken by the light to reach the earth from sun = 8 minutes & half minute = 510 seconds so, distance is speed x time Distance = [3 x 10^8]m x [510]seconds = [153 x 10^9]

Eight and a half minutes is equal to $510$ seconds, so the distance between the Earth and the Sun is about $510 \cdot (3 \times 10^8) = \boxed{1.53 \times 10^{11}}$ meters.

(You would input this as "1.53E+11".)

We have $v=\frac{s}{t} \Rightarrow s = t \cdot v$ . The speed of the light is $3 \cdot 10^8 m/s$ and the time it takes for the light to reach the earth is $8.5 min = 510s$ . Therefore, the distance is calculated by, $s = 510 \cdot 3 \cdot 10^8 = 1.53 \cdot 10^{11}m$

Total time takes = $30 + 8 * 48 = 510 sec$

Speed of light = $3 * 10 ^8 m/sec$

Total distance = $510 * 3 * 10 ^8 = 1.53E+11 m$