Location, Location, Location

Logic Level 2

62 63 = 1 \Large 62 - 63 = 1

Which digit should be moved to make the above (base 10) equation correct?

Note: The operators cannot be moved.

the 6 in 62 2 the 6 in 63 3 1

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1 solution

2 6 63 = 1 \Large 2^{6} - 63 = 1 .

Amazing deception! Please forgive me if I use this as a teaching tool in the future :) it's just too cool.

William Nathanael Supriadi - 4 years, 7 months ago

👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻👏🏻

Rico Lee - 4 years, 7 months ago

Ha ha.... Great question! :0)

Geoff Pilling - 4 years, 7 months ago

+1 Playing devil's advocate, why can't any of the other numbers work?

Calvin Lin Staff - 4 years, 8 months ago

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Nice try, Mr. Staff! The proof is much more boring than the solution, sadly. By the way, is this really level 2? It's difficult!

William Nathanael Supriadi - 4 years, 6 months ago

Clever, perhaps TOO clever - Stewie - Seriously, good one!

Terry Smith - 4 years, 7 months ago

Didn't think of that!! (+1)

Noel Lo - 4 years, 7 months ago

Didn't think of that

Arya Kusuma - 4 years, 7 months ago

'The operators can not be moved' implies that new ones can not be added. But exponentation has been added here.

Anthony Cutler - 4 years, 6 months ago

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"The operators cannot be moved" only refers to the operators already present, so I don't see how that invalidates the introduction of exponentiation implicit in the repositioning of the first 6 6 . In any event, the question was simply designed to prompt people to "think outside the box" to find an answer. Logic questions can be tricky to word so that no misunderstandings arise, so I'm sorry if that has been the case for you. However, enough people have come up with the intended answer that I feel justified in leaving the wording as is.

Brian Charlesworth - 4 years, 6 months ago

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Well.......................................................................................

Vishwash Kumar ΓΞΩ - 4 years, 6 months ago

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@Vishwash Kumar Γξω @Brian Charlesworth If adding operators are allowed then this can also be a solution . Right 6/2 - 6/3 = 1 Without shifting anything .........................................................................................................................................................

Vishwash Kumar ΓΞΩ - 4 years, 6 months ago

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@Vishwash Kumar Γξω Well, in this case you've moved two of the digits, as well as adding two division signs. With the exponentiation solution, only one digit is moved and no actual "marks" are added, since positioning the 6 6 to the upper right of the 2 2 implies exponentiation without adding any extra signs.

When I first posted this problem I expected some disputes but they never came, and now that the problem has stood the test of time, (1253 views so far and 224 solvers), I don't think that there is any point in changing the wording. It was just meant as a fun problem with an interesting twist. :)

Brian Charlesworth - 4 years, 6 months ago

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@Brian Charlesworth yeep.......................................

Vishwash Kumar ΓΞΩ - 4 years, 6 months ago

@Vishwash Kumar Γξω Well at least your solution isn't one of the choices... And you must shift something.

William Nathanael Supriadi - 4 years, 6 months ago

Amazing Problem !!

Nashita Rahman - 4 years, 4 months ago

Didn't think of that .

Vishwash Kumar ΓΞΩ - 4 years, 7 months ago

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