A locomotive of mass starts moving on the -axis from the origin such that its velocity (v) is directly proportional to the square root of its displacement; . Find the total work done by all of the forces acting on the locomotive in the first seconds of its motion.
The answer will be a function and the constant of proportionality which relates the velocity and the square root of the displacement. Find the sum of the exponents on and in the function .
PS: In fact, there is a much shorter way to solve this problem, one which requires only two steps. If you can figure it out, put it down as a solution. This alternative solution does not require calculus or any difficult mathematics. It simply requires you to see the problem which I have given in a little more detail
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v = k x
⇒ v 2 = k 2 x
And Eq. of motion v 2 = v 0 2 + 2 a x
⇒ a = 2 k 2 , v 0 = 0
s = 2 1 a t 2 = 4 k 2 t 2
⇒ W d o n e = 8 m k 2 ⋅ k 2 t 2 = 8 m k 4 t 2
∴ 7
I hope this is the easiest method! (Well I used Calculus!)